42 lines
2.0 KiB
Markdown
42 lines
2.0 KiB
Markdown
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## Difficulty
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50/100
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## Category
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Cryptography
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## How To Solve
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The challenge is a simple enigma encoding. You are given the ciphertext and the plug board.
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It can be bruteforced with the following tool: https://github.com/the-lambda-way/bruteforce-enigma
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Once cloned, you have to add the ciphertext and the plugboard to the crack_enigma.cpp file.
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```cpp
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Ciphertext ct = "BYNCXFMMWAESLCQMYZPFYFSFPYQFGXHYTKKMHORH";
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Plugboard plug = "BQ CR DI EJ KW MT OS PX UZ GH";
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```
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Then you just run `make && ./crack_enigma` and the answer should roll right out
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```
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Breaking enigma...
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# Score Refl Rotor Order Ring Pos Rotor Pos Text
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1 -225.605389 UKWB II III I 0 0 0 9 13 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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2 -225.605389 UKWB II III I 0 4 0 9 17 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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3 -225.605389 UKWB II III I 0 2 0 9 15 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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4 -225.605389 UKWB II III I 0 9 0 9 22 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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5 -225.605389 UKWB II III I 0 3 0 9 16 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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6 -225.605389 UKWB II III I 0 5 0 9 18 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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7 -225.605389 UKWB II III I 0 1 0 9 14 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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8 -225.605389 UKWB II III I 0 11 0 9 24 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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9 -225.605389 UKWB II III I 0 6 0 9 19 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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10 -225.605389 UKWB II III I 0 10 0 9 23 11 THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY
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Elapsed time: 0.83 seconds
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```
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## Hints
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- I hope you payed attention to the course automata and computability!
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- It might be useful information that my friend is German.
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## Flag
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IGCTF{THANKYOUALANTURINGITCOULDNOTHAVEBEENEASY}
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